|
To
derive the corresponding F-values from the values of the Wald statistics
one just needs to divide the Wald statistic by the corresponding degrees
of freedom. These values are shown here under the column headed Wald/d.f.
The v.r. or F value for YEAR in the least squares analysis of
variance shown further down is 48.99; this is the same as the corresponding Wald/d.f. value
shown alongside.
Note also that the estimated residual variance is the same in both
outputs, i.e. *units* stratum variance = 4.933 with 688 degrees of
freedom, which is the same as the residual m.s. value in the least
squares analysis of variance.
|
|
*****
REML Variance Components Analysis *****
Response Variate : WEANWT
*** Approximate stratum variances ***
Effective d.f.
*units*
4.933 688.00
*** Wald tests for fixed effects ***
|
Fixed term
|
Wald statistic
|
d.f.
|
Wald/d.f.
|
Chi-sq prob
|
|
* Sequentially adding terms to
fixed model
|
|
YEAR
|
244.93
|
5
|
48.99
|
<0.001
|
|
SEX
|
11.35
|
1
|
11.35
|
<0.001
|
|
AGEWEAN
|
69.78
|
1
|
69.78
|
<0.001
|
|
DL
|
30.72
|
1
|
30.72
|
<0.001
|
|
DQ
|
55.91
|
1
|
55.91
|
<0.001
|
|
RAM_BRD
|
9.10
|
1
|
9.10
|
0.003
|
|
EWE_BRD
|
6.13
|
1
|
6.13
|
0.013
|
|
Least Squares analysis
| Accumulated analysis of variance |
|
| Change
|
d.f
|
s.s.
|
m.s.
|
v.r.
|
|
+ YEAR
|
5
|
1208.149
|
241.630
|
48.99
|
|
+ SEX
|
1
|
55.983
|
55.983
|
11.35
|
|
+ AGEWEAN
|
1
|
344.206
|
344.206
|
69.78
|
|
+ DL
|
1
|
151.513
|
151.513
|
30.72
|
|
+ DQ
|
1
|
275.795
|
275.795
|
55.19
|
|
+ RAM_BRD
|
1
|
44.881
|
44.881
|
9.10
|
|
+ EWE_BRD
|
1
|
30.223
|
30.223
|
6.13
|
|
Residual
|
688
|
3393.701
|
4.933
|
|
|
Total
|
699
|
5504.450
|
7.875
|
|
|
